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Current Path : /proc/thread-self/root/lib64/python2.7/Demo/scripts/ |
Current File : //proc/thread-self/root/lib64/python2.7/Demo/scripts/unbirthday.py |
#! /usr/bin/python2.7 # Calculate your unbirthday count (see Alice in Wonderland). # This is defined as the number of days from your birth until today # that weren't your birthday. (The day you were born is not counted). # Leap years make it interesting. import sys import time import calendar def main(): if sys.argv[1:]: year = int(sys.argv[1]) else: year = int(raw_input('In which year were you born? ')) if 0 <= year < 100: print "I'll assume that by", year, year = year + 1900 print 'you mean', year, 'and not the early Christian era' elif not (1850 <= year <= time.localtime()[0]): print "It's hard to believe you were born in", year return if sys.argv[2:]: month = int(sys.argv[2]) else: month = int(raw_input('And in which month? (1-12) ')) if not (1 <= month <= 12): print 'There is no month numbered', month return if sys.argv[3:]: day = int(sys.argv[3]) else: day = int(raw_input('And on what day of that month? (1-31) ')) if month == 2 and calendar.isleap(year): maxday = 29 else: maxday = calendar.mdays[month] if not (1 <= day <= maxday): print 'There are no', day, 'days in that month!' return bdaytuple = (year, month, day) bdaydate = mkdate(bdaytuple) print 'You were born on', format(bdaytuple) todaytuple = time.localtime()[:3] todaydate = mkdate(todaytuple) print 'Today is', format(todaytuple) if bdaytuple > todaytuple: print 'You are a time traveler. Go back to the future!' return if bdaytuple == todaytuple: print 'You were born today. Have a nice life!' return days = todaydate - bdaydate print 'You have lived', days, 'days' age = 0 for y in range(year, todaytuple[0] + 1): if bdaytuple < (y, month, day) <= todaytuple: age = age + 1 print 'You are', age, 'years old' if todaytuple[1:] == bdaytuple[1:]: print 'Congratulations! Today is your', nth(age), 'birthday' print 'Yesterday was your', else: print 'Today is your', print nth(days - age), 'unbirthday' def format((year, month, day)): return '%d %s %d' % (day, calendar.month_name[month], year) def nth(n): if n == 1: return '1st' if n == 2: return '2nd' if n == 3: return '3rd' return '%dth' % n def mkdate((year, month, day)): # January 1st, in 0 A.D. is arbitrarily defined to be day 1, # even though that day never actually existed and the calendar # was different then... days = year*365 # years, roughly days = days + (year+3)//4 # plus leap years, roughly days = days - (year+99)//100 # minus non-leap years every century days = days + (year+399)//400 # plus leap years every 4 centirues for i in range(1, month): if i == 2 and calendar.isleap(year): days = days + 29 else: days = days + calendar.mdays[i] days = days + day return days if __name__ == "__main__": main()