shell bypass 403
UnknownSec Shell
:
/
proc
/
thread-self
/
root
/
proc
/
thread-self
/
root
/
lib64
/
python3.8
/ [
drwxr-xr-x
]
upload
mass deface
mass delete
console
info server
name :
nturl2path.py
"""Convert a NT pathname to a file URL and vice versa. This module only exists to provide OS-specific code for urllib.requests, thus do not use directly. """ # Testing is done through test_urllib. def url2pathname(url): """OS-specific conversion from a relative URL of the 'file' scheme to a file system path; not recommended for general use.""" # e.g. # ///C|/foo/bar/spam.foo # and # ///C:/foo/bar/spam.foo # become # C:\foo\bar\spam.foo import string, urllib.parse # Windows itself uses ":" even in URLs. url = url.replace(':', '|') if not '|' in url: # No drive specifier, just convert slashes if url[:4] == '////': # path is something like ////host/path/on/remote/host # convert this to \\host\path\on\remote\host # (notice halving of slashes at the start of the path) url = url[2:] components = url.split('/') # make sure not to convert quoted slashes :-) return urllib.parse.unquote('\\'.join(components)) comp = url.split('|') if len(comp) != 2 or comp[0][-1] not in string.ascii_letters: error = 'Bad URL: ' + url raise OSError(error) drive = comp[0][-1].upper() components = comp[1].split('/') path = drive + ':' for comp in components: if comp: path = path + '\\' + urllib.parse.unquote(comp) # Issue #11474 - handing url such as |c/| if path.endswith(':') and url.endswith('/'): path += '\\' return path def pathname2url(p): """OS-specific conversion from a file system path to a relative URL of the 'file' scheme; not recommended for general use.""" # e.g. # C:\foo\bar\spam.foo # becomes # ///C:/foo/bar/spam.foo import urllib.parse # First, clean up some special forms. We are going to sacrifice # the additional information anyway if p[:4] == '\\\\?\\': p = p[4:] if p[:4].upper() == 'UNC\\': p = '\\' + p[4:] elif p[1:2] != ':': raise OSError('Bad path: ' + p) if not ':' in p: # No drive specifier, just convert slashes and quote the name if p[:2] == '\\\\': # path is something like \\host\path\on\remote\host # convert this to ////host/path/on/remote/host # (notice doubling of slashes at the start of the path) p = '\\\\' + p components = p.split('\\') return urllib.parse.quote('/'.join(components)) comp = p.split(':', maxsplit=2) if len(comp) != 2 or len(comp[0]) > 1: error = 'Bad path: ' + p raise OSError(error) drive = urllib.parse.quote(comp[0].upper()) components = comp[1].split('\\') path = '///' + drive + ':' for comp in components: if comp: path = path + '/' + urllib.parse.quote(comp) return path
© 2024 UnknownSec